What horizontal force must be applied by the worker to maintain the motion?

A stockroom worker pushes a box with mass 11.1kg on a horizontal surface with a constant speed of 4.00 . The coefIficient of kinetic friction between the box and the surface is 0.240m/s.What horizontal force must be applied by the worker to maintain the motion?If the force calculated in part (A) is removed, how far does the box slide before coming to rest?Take the free fall acceleration to be = 9.80 m/s^2What horizontal force must be applied by the worker to maintain the motion?Normal force is equal to gravity Fn = m*g. Friction force is Ff = 0.24*Fn = 0.24*m*g. For box to move with constant velocity applied force should be equal friction force: F = Ff = 0.24*m*g.

When force removed, net force is equal to Ff, so acceleration is a = Ff/m = 0.24*g. Sliding would go for D = v^2/2a = v^2/(0.48g)