Thursday, January 26, 2012

What is the maximum displacement of the simple harmonic motion?

A 14.0 kg mass is connected to a spring with a spring constant of 90.0 N/m. The displacement is given by the expression x(t)=0.037 sin (omega t) m. What is the maximum displacement of the simple harmonic motion?What is the maximum displacement of the simple harmonic motion?Since the sine of anything can't exceed 1, A = 0.037 m.

I wonder if you're actually asking about the maximum velocity vmax.

If so, we need to find the oscillation angular rate omega.

omega = sqrt(k/m) = 2.535463 rad/s

vmax = omega*A = 0.09381212 m/s

No comments:

Post a Comment