How much additional distance will the car cover during the second of its motion?

A car stars from rest and accelerates at a constant rate in a straight line. In the first second the car covers a distance of 2.0 meters. How much additional distance will the car cover during the second of its motion?How much additional distance will the car cover during the second of its motion?Initial velocity = 0 m/s

Acceleration = ?

Displacement = 2.0 m

Time = 1 s



Displacement = (Init. Vel.)(Time)+(1/2)(Accel.)(Time^2)

Acceleration = 2[Displacement-(Init. Vel.)(Time)]/(Time^2)

Acceleration = 2*(2 m)/(1 s^2) = 4.0 m/s/s







Displacement one second later (from t=1 to t=2):



Velocity(1 sec) = Acceleration*Time = (4.0 m/s/s)(1 s) = 4 m/s

Displacement = ?

TIme = 1 sec

Acceleration = 4 m/s/s



Displacement = (4 m/s)(1 s)+(4.0 m/s/s)(1 s^2) = 8 m



Overall Displacement = 2.0 m + 8.0 m = 10.0 mHow much additional distance will the car cover during the second of its motion?i think an additional 4 meters making 6 meters in 2 seconds. Based on acceleration seeming to be +2 m/s/s