How much additional distance will the car cover during the second of its motion?

A car stars from rest and accelerates at a constant rate in a straight line. In the first second the car covers a distance of 2.0 meters. How much additional distance will the car cover during the second of its motion?How much additional distance will the car cover during the second of its motion?Given that the d=rt (d=distance, r=rate, and t=time) the velocity of the car is given by 2.0=r(1). Now since the rate of acceleration is constant...a=(v-vsub0)/t where v is the final velocity and vsub0 is the initial velocity. So (2-0)/1 =2m/s^2, distance=2^2=4mHow much additional distance will the car cover during the second of its motion?2 more meters.