What is the cyclic frequency of the resulting motion?

When an unknown weight W was suspended from a spring with an unknown force constant k it reached its equilibrium position and the spring was stretched by 56.9 cm because of the weight W .

Then the weight W was pulled further down to a position 65 cm (8.1 cm below its equilibrium position) and released, which caused an oscillation in the spring. Calculate the cyclic frequency of the resulting motion. The acceleration due to gravity is 9.8 m/s2. Answer in units of Hz.What is the cyclic frequency of the resulting motion?k = W/0.569

m =W/9.8

x = x0cos(wt), w = sqrt(k/m) = sqrt(9.8/0.569) = 17.22 rad/s or 2.74 Hz answerWhat is the cyclic frequency of the resulting motion?k = w / 0.569 N/m

= mg / 0.569



where m = mass



m/k = 0.569 / 9.8 = 0.5806



period of SHM

= 2 pi sq root [ m/k]



= 2 * pi * sq rt 0.5806



= 1.514 s



Frequency = 1/ 1.514 = 0.661 Hz



answer