A 160 g mass is attached to a spring and executes simple harmonic motion with a period of 0.250 s. If the total energy of the system is 2.90 J.What is the constant force of the spring and the amp of the motion?first convert 160g to kg. 160g= 0.16kg
period for a spring
T=2蟺鈭?m/k)
0.25 = 2蟺鈭?0.16/k)
0.0625=4蟺虏(0.16/k)
k=101 N/m
total energy = .5kA虏
2.90 = 0.5(101)A虏
A=0.240 m
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