How to Calculate Uniform Circular motion in horizontal xy plane?

A particle moves horizontally in uniform circular motion, over a

horizontal xy plane. At one instant, it moves through the point at coordinates (4.00 m,

4.00 m) with a velocity of i藛 00 . 5 鈭?m/s and an acceleration of j藛 +12.5 m/s2. What are the

(a) x and (b) y coordinates of the centre of the circular path?How to Calculate Uniform Circular motion in horizontal xy plane?If I understand your conditions correctly, in (x,y) notation, v = (0.5,0) and a = (0,12.5). Centripetal acceleration a is toward the center. Since a is along the y axis, the center is directly above the point (4,4). And since a = v^2/r, r = v^2/a = 0.02 m. Thus the center is at (4 m, 4.02 m). Of course, with those spaces and the floating minus sign or dash, I suppose "i藛 00 . 5 鈭?" could easily be something other than 0.5. If so, just substitute it for v to get the correct value for r.How to Calculate Uniform Circular motion in horizontal xy plane?Thank-you.

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