What is the tension in the wire while the masses are in motion?

A 3.2 m long cylindrical steel wire with a cross-sectional diameter of 6.4 mm is placed over a frictionless pulley, with one end of the wire connected to a mass 6.6 kg and the other

end connected to a mass 3.3 kg. The acceleration of gravity is 9.8 m/s^2. Young's modulus for steel Y = 2 X10^11 Pa.



**What is the tension in the wire while the masses are in motion? Answer in units of N.



**By how much does the wire stretch while the masses are in motion? Answer in units of mm.What is the tension in the wire while the masses are in motion?鈭咶 = g(6.6-3.3) = 32.34 N

a = 鈭咶/m = 32.34/(6.6+3.3) = 3.2667 m/s虏



T = m1(g-a) = m2(g+a) = 43.12 N



鈭哃 = 蟽L/E = TL/AE = 43.12*3.2/[蟺/4(.0064虏)*2E11] = 2.145E-5m = 2.145E-2 mmWhat is the tension in the wire while the masses are in motion?The motion is irrelevant.



T = T1 + T2 = M1*g + M2*g = 9.9g = 98.01N



Stergth is from Young's modulus stress/strain equation:

E = (T/A0)/(DL/L0) where DL = delta-L (stretch)



Calculate these from the data: A0 = cross-section area of the wire (pi*r^2) then plug %26amp; chug to get the answer.



be careful of the units (N, m, mm, Pa)