How to find the radius of a circular motion?

A particle with a charge of 1.60e-19 C and a mass of 1.67e-27 kg moves with a speed of 2.00e5 m/s perpendicular to a magnetic field of 0.0100 T. What will be the radius of its circular motion?How to find the radius of a circular motion?Circular Path from Magnetic Field with NO voltage



r = mv/qB



r=(1.67e-27 kg) * (2.00e5 (m / s) / (1.60e-19 C) * (0.0100 T)

= 2.0875 脳 10-1 m

= 0.21 metersHow to find the radius of a circular motion?For circular motion:

F = ma

a = v^2 / r

F = mv^2 / r



But in a magnetic field, F = qvB

Set the 2 different forces equal to each other as they are really the same force. Just different equations:



qvB = mv^2 / r

rqvB = mv^2

r = mv^2 / qvB



r = mv / qB



r = (1.67e-27 kg)(2.00e5 m/s) / (1.60e-19 C)(0.0100 T)